What the extra zero changes in a straight-bet model
Adding a losing outcome while keeping the winning payout unchanged reduces expected return.
The distinction that matters
Assume a 38-pocket wheel with one winning pocket for a single-number bet and 35-to-1 profit. Expected net result per unit is 35/38 − 37/38 = −2/38, approximately −5.2632%. The denominator and the number of losing outcomes both change compared with a 37-pocket model.
A worked example
On hypothetical C$380 turnover, expected cost is C$20. If you mistakenly use 37 as the denominator while retaining 37 losing outcomes, the probabilities do not sum to one. Counting the outcomes before doing the arithmetic prevents that inconsistency.
Your next steps
- Count the zero and double-zero pockets separately.
- Check the actual payout for the bet.
- Confirm that outcome probabilities sum to one.
- Compare fixed turnover amounts when comparing expected costs.
Where this answer stops
The label 'American' is not a complete contract for every online variant. This derivation applies only to the stated 38-pocket, equal-probability, 35-to-1 model and is not a recommendation to play it.
Sources & reading
Primary references support the factual context below. Explanations, worked examples and calculations are original Northline analysis. Read how we handle evidence.
- BCLC — double-zero roulette payout schedule
Primary British Columbia rules document: section 1.0, payout schedule. Cited only as a documented mathematical rules example, not as Ontario law, operator terms or evidence of availability in Ontario. Accessed .
An editorial review date is not a new policy effective date. Always check the current source for operator-specific conditions.
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